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2/5+2/5c=1/5(3c+3)
We move all terms to the left:
2/5+2/5c-(1/5(3c+3))=0
Domain of the equation: 5c!=0
c!=0/5
c!=0
c∈R
Domain of the equation: 5(3c+3))!=0We calculate fractions
c∈R
(10c3/(125c^23+(-(1*5c)/(125c^23=0
We do not support ecpression: c^23
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