2/5(z+1)=1

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Solution for 2/5(z+1)=1 equation: 



2/5(z+1)=1

We move all terms to the left:

2/5(z+1)-(1)=0



Domain of the equation: 5(z+1)!=0

z∈R



We multiply all the terms by the denominator


-1*5(z+1)+2=0

Wy multiply elements

-5z(z+2=0

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