2/5(x-2)+3/7=1/7(x+1)

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Solution for 2/5(x-2)+3/7=1/7(x+1) equation: 



2/5(x-2)+3/7=1/7(x+1)

We move all terms to the left:

2/5(x-2)+3/7-(1/7(x+1))=0



Domain of the equation: 5(x-2)!=0

x∈R





Domain of the equation: 7(x+1))!=0

x∈R



We calculate fractions


(98xx/(5(x-2)*7(x+1))*7)+(-5xx/(5(x-2)*7(x+1))*7)+(15xx/(5(x-2)*7(x+1))*7)=0



We calculate terms in parentheses: +(98xx/(5(x-2)*7(x+1))*7), so:

98xx/(5(x-2)*7(x+1))*7

We multiply all the terms by the denominator


98xx

Back to the equation:

+(98xx)





We calculate terms in parentheses: +(-5xx/(5(x-2)*7(x+1))*7), so:

-5xx/(5(x-2)*7(x+1))*7

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)





We calculate terms in parentheses: +(15xx/(5(x-2)*7(x+1))*7), so:

15xx/(5(x-2)*7(x+1))*7

We multiply all the terms by the denominator


15xx

Back to the equation:

+(15xx)



We get rid of parentheses

98xx-5xx+15xx=0

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