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2/5(x+4)+3/2(x+2)=-3
We move all terms to the left:
2/5(x+4)+3/2(x+2)-(-3)=0
Domain of the equation: 5(x+4)!=0
x∈R
Domain of the equation: 2(x+2)!=0We add all the numbers together, and all the variables
x∈R
2/5(x+4)+3/2(x+2)+3=0
We calculate fractions
(4xx/(5(x+4)*2(x+2))+(15xx/(5(x+4)*2(x+2))+3=0
We can not solve this equation
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