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2/5(x+4)+(-7)=-16
We move all terms to the left:
2/5(x+4)+(-7)-(-16)=0
Domain of the equation: 5(x+4)!=0We add all the numbers together, and all the variables
x∈R
2/5(x+4)+9=0
We multiply all the terms by the denominator
9*5(x+4)+2=0
Wy multiply elements
45x(x+2=0
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