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2/5(x+2)=-3
We move all terms to the left:
2/5(x+2)-(-3)=0
Domain of the equation: 5(x+2)!=0We add all the numbers together, and all the variables
x∈R
2/5(x+2)+3=0
We multiply all the terms by the denominator
3*5(x+2)+2=0
Wy multiply elements
15x(x+2=0
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