2/5(r-2)=-3/4(12+r)

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Solution for 2/5(r-2)=-3/4(12+r) equation: 



2/5(r-2)=-3/4(12+r)

We move all terms to the left:

2/5(r-2)-(-3/4(12+r))=0



Domain of the equation: 5(r-2)!=0

r∈R





Domain of the equation: 4(12+r))!=0

r∈R



We add all the numbers together, and all the variables

2/5(r-2)-(-3/4(r+12))=0

We calculate fractions


(8rr/(5(r-2)*4(r+12)))+(-(-15rr)/(5(r-2)*4(r+12)))=0



We calculate terms in parentheses: +(8rr/(5(r-2)*4(r+12))), so:

8rr/(5(r-2)*4(r+12))

We multiply all the terms by the denominator


8rr

Back to the equation:

+(8rr)





We calculate terms in parentheses: +(-(-15rr)/(5(r-2)*4(r+12))), so:

-(-15rr)/(5(r-2)*4(r+12))

We multiply all the terms by the denominator


-(-15rr)

We get rid of parentheses

15rr

Back to the equation:

+(15rr)

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