2/5(r+2)=3/20(r-4)

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Solution for 2/5(r+2)=3/20(r-4) equation: 



2/5(r+2)=3/20(r-4)

We move all terms to the left:

2/5(r+2)-(3/20(r-4))=0



Domain of the equation: 5(r+2)!=0

r∈R





Domain of the equation: 20(r-4))!=0

r∈R



We calculate fractions


(40rr/(5(r+2)*20(r-4)))+(-15rr/(5(r+2)*20(r-4)))=0



We calculate terms in parentheses: +(40rr/(5(r+2)*20(r-4))), so:

40rr/(5(r+2)*20(r-4))

We multiply all the terms by the denominator


40rr

Back to the equation:

+(40rr)





We calculate terms in parentheses: +(-15rr/(5(r+2)*20(r-4))), so:

-15rr/(5(r+2)*20(r-4))

We multiply all the terms by the denominator


-15rr

Back to the equation:

+(-15rr)



We get rid of parentheses

40rr-15rr=0

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