2/5(j-40)=-4

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Solution for 2/5(j-40)=-4 equation: 



2/5(j-40)=-4

We move all terms to the left:

2/5(j-40)-(-4)=0



Domain of the equation: 5(j-40)!=0

j∈R



We add all the numbers together, and all the variables

2/5(j-40)+4=0

We multiply all the terms by the denominator


4*5(j-40)+2=0

Wy multiply elements

20j(j+2=0

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