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2/5(c-2)=1/10(c-1)
We move all terms to the left:
2/5(c-2)-(1/10(c-1))=0
Domain of the equation: 5(c-2)!=0
c∈R
Domain of the equation: 10(c-1))!=0We calculate fractions
c∈R
(20cc/(5(c-2)*10(c-1)))+(-5cc/(5(c-2)*10(c-1)))=0
We calculate terms in parentheses: +(20cc/(5(c-2)*10(c-1))), so:
20cc/(5(c-2)*10(c-1))
We multiply all the terms by the denominator
20cc
Back to the equation:
+(20cc)
We calculate terms in parentheses: +(-5cc/(5(c-2)*10(c-1))), so:We get rid of parentheses
-5cc/(5(c-2)*10(c-1))
We multiply all the terms by the denominator
-5cc
Back to the equation:
+(-5cc)
20cc-5cc=0
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