2/5(9-t)=28

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Solution for 2/5(9-t)=28 equation: 



2/5(9-t)=28

We move all terms to the left:

2/5(9-t)-(28)=0



Domain of the equation: 5(9-t)!=0

t∈R



We add all the numbers together, and all the variables

2/5(-1t+9)-28=0

We multiply all the terms by the denominator


-28*5(-1t+9)+2=0

Wy multiply elements

-140t(-+2=0

We use the square of the difference formula

-140t(-2=0

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