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2/5(4c-2)=c+1
We move all terms to the left:
2/5(4c-2)-(c+1)=0
Domain of the equation: 5(4c-2)!=0We get rid of parentheses
c∈R
2/5(4c-2)-c-1=0
We multiply all the terms by the denominator
-c*5(4c-2)-1*5(4c-2)+2=0
Wy multiply elements
-5c^2(4-5c(4+2=0
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