2/5(3x+1)=1/3(2x-6)

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Solution for 2/5(3x+1)=1/3(2x-6) equation:



2/5(3x+1)=1/3(2x-6)
We move all terms to the left:
2/5(3x+1)-(1/3(2x-6))=0
Domain of the equation: 5(3x+1)!=0
x∈R
Domain of the equation: 3(2x-6))!=0
x∈R
We calculate fractions
(6x2/(5(3x+1)*3(2x-6)))+(-5x3/(5(3x+1)*3(2x-6)))=0
We calculate terms in parentheses: +(6x2/(5(3x+1)*3(2x-6))), so:
6x2/(5(3x+1)*3(2x-6))
We multiply all the terms by the denominator
6x2
We add all the numbers together, and all the variables
6x^2
Back to the equation:
+(6x^2)
We calculate terms in parentheses: +(-5x3/(5(3x+1)*3(2x-6))), so:
-5x3/(5(3x+1)*3(2x-6))
We multiply all the terms by the denominator
-5x3
We add all the numbers together, and all the variables
-5x^3
We do not support expression: x^3

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