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2/5(2x+3)=x+1
We move all terms to the left:
2/5(2x+3)-(x+1)=0
Domain of the equation: 5(2x+3)!=0We get rid of parentheses
x∈R
2/5(2x+3)-x-1=0
We multiply all the terms by the denominator
-x*5(2x+3)-1*5(2x+3)+2=0
Wy multiply elements
-5x^2(2-5x(2+2=0
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