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2/5(10x-5)=-26
We move all terms to the left:
2/5(10x-5)-(-26)=0
Domain of the equation: 5(10x-5)!=0We add all the numbers together, and all the variables
x∈R
2/5(10x-5)+26=0
We multiply all the terms by the denominator
26*5(10x-5)+2=0
Wy multiply elements
130x(1+2=0
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