2/5(10x-20)-6=7x-17

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Solution for 2/5(10x-20)-6=7x-17 equation:



2/5(10x-20)-6=7x-17
We move all terms to the left:
2/5(10x-20)-6-(7x-17)=0
Domain of the equation: 5(10x-20)!=0
x∈R
We get rid of parentheses
2/5(10x-20)-7x+17-6=0
We multiply all the terms by the denominator
-7x*5(10x-20)+17*5(10x-20)-6*5(10x-20)+2=0
Wy multiply elements
-35x^2(1+85x(1-30x(1+2=0

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