2/5(10x+35)=1/8(16x+80)

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Solution for 2/5(10x+35)=1/8(16x+80) equation: 



2/5(10x+35)=1/8(16x+80)

We move all terms to the left:

2/5(10x+35)-(1/8(16x+80))=0



Domain of the equation: 5(10x+35)!=0

x∈R





Domain of the equation: 8(16x+80))!=0

x∈R



We calculate fractions


(16x1/(5(10x+35)*8(16x+80)))+(-5x1/(5(10x+35)*8(16x+80)))=0



We calculate terms in parentheses: +(16x1/(5(10x+35)*8(16x+80))), so:

16x1/(5(10x+35)*8(16x+80))

We multiply all the terms by the denominator


16x1

We add all the numbers together, and all the variables

16x

Back to the equation:

+(16x)





We calculate terms in parentheses: +(-5x1/(5(10x+35)*8(16x+80))), so:

-5x1/(5(10x+35)*8(16x+80))

We multiply all the terms by the denominator


-5x1

We add all the numbers together, and all the variables

-5x

Back to the equation:

+(-5x)



We get rid of parentheses

16x-5x=0

We add all the numbers together, and all the variables

11x=0

x=0/11

x=0

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