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x in (-oo:+oo)
(2/5)*(1-(5*x)) = (-1/2)*(4*x+3) // - (-1/2)*(4*x+3)
(2/5)*(1-(5*x))-((-1/2)*(4*x+3)) = 0
(2/5)*(1-5*x)+(1/2)*(4*x+3) = 0
2/5*(1-5*x)+1/2*(4*x+3) = 0
2/5*(1-5*x)+1/2*(4*x+3) = 0
19/10 = 0
19/10 = 0
19/10 = 0 // * 10
19 = 0
x belongs to the empty set
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