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2/4x+2x=130
We move all terms to the left:
2/4x+2x-(130)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
2x+2/4x-130=0
We multiply all the terms by the denominator
2x*4x-130*4x+2=0
Wy multiply elements
8x^2-520x+2=0
a = 8; b = -520; c = +2;
Δ = b2-4ac
Δ = -5202-4·8·2
Δ = 270336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{270336}=\sqrt{4096*66}=\sqrt{4096}*\sqrt{66}=64\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-520)-64\sqrt{66}}{2*8}=\frac{520-64\sqrt{66}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-520)+64\sqrt{66}}{2*8}=\frac{520+64\sqrt{66}}{16} $
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