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2/4x+2/3x=7
We move all terms to the left:
2/4x+2/3x-(7)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
6x/12x^2+8x/12x^2-7=0
We multiply all the terms by the denominator
6x+8x-7*12x^2=0
We add all the numbers together, and all the variables
14x-7*12x^2=0
Wy multiply elements
-84x^2+14x=0
a = -84; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-84)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-84}=\frac{-28}{-168} =1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-84}=\frac{0}{-168} =0 $
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