2/4r+2(3/4r-1)=1/4r+6

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Solution for 2/4r+2(3/4r-1)=1/4r+6 equation: 


r in (-oo:+oo)

2*((3/4)*r-1)+(2/4)*r = (1/4)*r+6 // - (1/4)*r+6

2*((3/4)*r-1)+(2/4)*r-((1/4)*r)-6 = 0

2*((3/4)*r-1)+(2/4)*r+(-1/4)*r-6 = 0

2*(3/4*r-1)+r/2-r/4-6 = 0

(4*2^2*(3/4*r-1))/(2*4)+(4*r)/(2*4)+(2*(-r))/(2*4)+(-6*2*4)/(2*4) = 0

4*2^2*(3/4*r-1)+4*r+2*(-r)-6*2*4 = 0

16*r-2*r-48-16 = 0

14*r-48-16 = 0

14*r-64 = 0

(14*r-64)/(2*4) = 0

(14*r-64)/(2*4) = 0 // * 2*4

14*r-64 = 0

14*r-64 = 0 // + 64

14*r = 64 // : 14

r = 64/14

r = 32/7

r = 32/7

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