2/4=2x2x2x2=16

Solution for 2/4=2x2x2x2=16 equation:

2/4=2x^2x2x^2=16

We move all terms to the left:

2/4-(2x^2x2x^2)=0

We multiply all the terms by the denominator


-2x^2x2x^2*4+2=0

Wy multiply elements

-8x^2+2=0

a = -8; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-8)·2
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*-8}=\frac{-8}{-16}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*-8}=\frac{8}{-16}
=-1/2
$