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2/4(2d+3)=3/5(3d-5)
We move all terms to the left:
2/4(2d+3)-(3/5(3d-5))=0
Domain of the equation: 4(2d+3)!=0
d∈R
Domain of the equation: 5(3d-5))!=0We calculate fractions
d∈R
(10d3/(4(2d+3)*5(3d-5)))+(-12d2/(4(2d+3)*5(3d-5)))=0
We calculate terms in parentheses: +(10d3/(4(2d+3)*5(3d-5))), so:
10d3/(4(2d+3)*5(3d-5))
We multiply all the terms by the denominator
10d3
We add all the numbers together, and all the variables
10d^3
We do not support edpression: d^3
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