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2/3y=4y-1
We move all terms to the left:
2/3y-(4y-1)=0
Domain of the equation: 3y!=0We get rid of parentheses
y!=0/3
y!=0
y∈R
2/3y-4y+1=0
We multiply all the terms by the denominator
-4y*3y+1*3y+2=0
Wy multiply elements
-12y^2+3y+2=0
a = -12; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-12)·2
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{105}}{2*-12}=\frac{-3-\sqrt{105}}{-24} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{105}}{2*-12}=\frac{-3+\sqrt{105}}{-24} $
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