2/3y-5=27

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Solution for 2/3y-5=27 equation: 



2/3y-5=27

We move all terms to the left:

2/3y-5-(27)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

2/3y-32=0

We multiply all the terms by the denominator


-32*3y+2=0

Wy multiply elements

-96y+2=0

We move all terms containing y to the left, all other terms to the right

-96y=-2

y=-2/-96

y=1/48

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