2/3y-1/2y=1/6y-2

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Solution for 2/3y-1/2y=1/6y-2 equation: 


y in (-oo:+oo)

(2/3)*y-((1/2)*y) = (1/6)*y-2 // - (1/6)*y-2

(2/3)*y-((1/2)*y)-((1/6)*y)+2 = 0

(2/3)*y+(-1/2)*y+(-1/6)*y+2 = 0

2 = 0

y belongs to the empty set

y belongs to the empty set

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