2/3y-(y+1/4)=1/12(y+4)

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Solution for 2/3y-(y+1/4)=1/12(y+4) equation: 


y in (-oo:+oo)

(2/3)*y-y-(1/4) = (1/12)*(y+4) // - (1/12)*(y+4)

(2/3)*y-((1/12)*(y+4))-y-(1/4) = 0

(-1/12)*(y+4)+(2/3)*y-y-1/4 = 0

(2*y)/3-1/12*(y+4)-y-1/4 = 0

(-1/12*3*4*(y+4))/(3*4)+(2*4*y)/(3*4)+(3*4*(-y))/(3*4)+(-1*3)/(3*4) = 0

2*4*y-1/12*3*4*(y+4)+3*4*(-y)-1*3 = 0

7*y-12*y-4-3 = 0

-5*y-4-3 = 0

-5*y-7 = 0

(-5*y-7)/(3*4) = 0

(-5*y-7)/(3*4) = 0 // * 3*4

-5*y-7 = 0

-5*y-7 = 0 // + 7

-5*y = 7 // : -5

y = 7/(-5)

y = -7/5

y = -7/5

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