2/3y+6=10

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Solution for 2/3y+6=10 equation: 



2/3y+6=10

We move all terms to the left:

2/3y+6-(10)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

2/3y-4=0

We multiply all the terms by the denominator


-4*3y+2=0

Wy multiply elements

-12y+2=0

We move all terms containing y to the left, all other terms to the right

-12y=-2

y=-2/-12

y=1/6

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