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2/3y+1/6y=10
We move all terms to the left:
2/3y+1/6y-(10)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 6y!=0We calculate fractions
y!=0/6
y!=0
y∈R
12y/18y^2+3y/18y^2-10=0
We multiply all the terms by the denominator
12y+3y-10*18y^2=0
We add all the numbers together, and all the variables
15y-10*18y^2=0
Wy multiply elements
-180y^2+15y=0
a = -180; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-180)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-180}=\frac{-30}{-360} =1/12 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-180}=\frac{0}{-360} =0 $
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