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2/3xx-7=-5+2/3x
We move all terms to the left:
2/3xx-7-(-5+2/3x)=0
Domain of the equation: 3xx!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3xx-(2/3x-5)-7=0
We get rid of parentheses
2/3xx-2/3x+5-7=0
We calculate fractions
6x/9x^2+(-6x)/9x^2+5-7=0
We add all the numbers together, and all the variables
6x/9x^2+(-6x)/9x^2-2=0
We multiply all the terms by the denominator
6x+(-6x)-2*9x^2=0
Wy multiply elements
-18x^2+6x+(-6x)=0
We get rid of parentheses
-18x^2+6x-6x=0
We add all the numbers together, and all the variables
-18x^2=0
a = -18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-18)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-36}=0$
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