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2/3x=2x-128
We move all terms to the left:
2/3x-(2x-128)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-2x+128=0
We multiply all the terms by the denominator
-2x*3x+128*3x+2=0
Wy multiply elements
-6x^2+384x+2=0
a = -6; b = 384; c = +2;
Δ = b2-4ac
Δ = 3842-4·(-6)·2
Δ = 147504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{147504}=\sqrt{16*9219}=\sqrt{16}*\sqrt{9219}=4\sqrt{9219}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(384)-4\sqrt{9219}}{2*-6}=\frac{-384-4\sqrt{9219}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(384)+4\sqrt{9219}}{2*-6}=\frac{-384+4\sqrt{9219}}{-12} $
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