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2/3x=1/5x=7
We move all terms to the left:
2/3x-(1/5x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3x-(+1/5x)=0
We get rid of parentheses
2/3x-1/5x=0
We calculate fractions
10x/15x^2+(-3x)/15x^2=0
We multiply all the terms by the denominator
10x+(-3x)=0
We get rid of parentheses
10x-3x=0
We add all the numbers together, and all the variables
7x=0
x=0/7
x=0
Równanie nie ma rozwiązania
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