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2/3x-9-2x+2=2=1
We move all terms to the left:
2/3x-9-2x+2-(2)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-2x+2/3x-9=0
We multiply all the terms by the denominator
-2x*3x-9*3x+2=0
Wy multiply elements
-6x^2-27x+2=0
a = -6; b = -27; c = +2;
Δ = b2-4ac
Δ = -272-4·(-6)·2
Δ = 777
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{777}}{2*-6}=\frac{27-\sqrt{777}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{777}}{2*-6}=\frac{27+\sqrt{777}}{-12} $
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