2/3x-8(2x+1)=1/6x+6

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Solution for 2/3x-8(2x+1)=1/6x+6 equation: 



2/3x-8(2x+1)=1/6x+6

We move all terms to the left:

2/3x-8(2x+1)-(1/6x+6)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 6x+6)!=0

x∈R



We multiply parentheses

2/3x-16x-(1/6x+6)-8=0

We get rid of parentheses

2/3x-16x-1/6x-6-8=0

We calculate fractions


-16x+12x/18x^2+(-3x)/18x^2-6-8=0

We add all the numbers together, and all the variables

-16x+12x/18x^2+(-3x)/18x^2-14=0

We multiply all the terms by the denominator


-16x*18x^2+12x+(-3x)-14*18x^2=0

We add all the numbers together, and all the variables

12x-16x*18x^2+(-3x)-14*18x^2=0

Wy multiply elements

-288x^3-252x^2+12x+(-3x)=0

We get rid of parentheses

-288x^3-252x^2+12x-3x=0

We do not support expression: x^3

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