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2/3x-7=x-15
We move all terms to the left:
2/3x-7-(x-15)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-x+15-7=0
We multiply all the terms by the denominator
-x*3x+15*3x-7*3x+2=0
Wy multiply elements
-3x^2+45x-21x+2=0
We add all the numbers together, and all the variables
-3x^2+24x+2=0
a = -3; b = 24; c = +2;
Δ = b2-4ac
Δ = 242-4·(-3)·2
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-10\sqrt{6}}{2*-3}=\frac{-24-10\sqrt{6}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+10\sqrt{6}}{2*-3}=\frac{-24+10\sqrt{6}}{-6} $
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