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2/3x-5=5x+8
We move all terms to the left:
2/3x-5-(5x+8)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-5x-8-5=0
We multiply all the terms by the denominator
-5x*3x-8*3x-5*3x+2=0
Wy multiply elements
-15x^2-24x-15x+2=0
We add all the numbers together, and all the variables
-15x^2-39x+2=0
a = -15; b = -39; c = +2;
Δ = b2-4ac
Δ = -392-4·(-15)·2
Δ = 1641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{1641}}{2*-15}=\frac{39-\sqrt{1641}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{1641}}{2*-15}=\frac{39+\sqrt{1641}}{-30} $
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