2/3x-5/9x=-1

Solution for 2/3x-5/9x=-1 equation:

2/3x-5/9x=-1

We move all terms to the left:

2/3x-5/9x-(-1)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 9x!=0

x!=0/9

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-5/9x+1=0

We calculate fractions


18x/27x^2+(-15x)/27x^2+1=0

We multiply all the terms by the denominator


18x+(-15x)+1*27x^2=0

Wy multiply elements

27x^2+18x+(-15x)=0

We get rid of parentheses

27x^2+18x-15x=0

We add all the numbers together, and all the variables

27x^2+3x=0

a = 27; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·27·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*27}=\frac{-6}{54}
=-1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*27}=\frac{0}{54}
=0
$