2/3x-4=5/6x+7

Solution for 2/3x-4=5/6x+7 equation:

2/3x-4=5/6x+7

We move all terms to the left:

2/3x-4-(5/6x+7)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x+7)!=0

x∈R


We get rid of parentheses

2/3x-5/6x-7-4=0

We calculate fractions


12x/18x^2+(-15x)/18x^2-7-4=0

We add all the numbers together, and all the variables

12x/18x^2+(-15x)/18x^2-11=0

We multiply all the terms by the denominator


12x+(-15x)-11*18x^2=0

Wy multiply elements

-198x^2+12x+(-15x)=0

We get rid of parentheses

-198x^2+12x-15x=0

We add all the numbers together, and all the variables

-198x^2-3x=0

a = -198; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-198)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-198}=\frac{0}{-396}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-198}=\frac{6}{-396}
=-1/66
$