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2/3x-35=x-50
We move all terms to the left:
2/3x-35-(x-50)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-x+50-35=0
We multiply all the terms by the denominator
-x*3x+50*3x-35*3x+2=0
Wy multiply elements
-3x^2+150x-105x+2=0
We add all the numbers together, and all the variables
-3x^2+45x+2=0
a = -3; b = 45; c = +2;
Δ = b2-4ac
Δ = 452-4·(-3)·2
Δ = 2049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2049}}{2*-3}=\frac{-45-\sqrt{2049}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2049}}{2*-3}=\frac{-45+\sqrt{2049}}{-6} $
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