2/3x-3(x+1)=-2x-1/3(6-x

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Solution for 2/3x-3(x+1)=-2x-1/3(6-x equation: 



2/3x-3(x+1)=-2x-1/3(6-x

We move all terms to the left:

2/3x-3(x+1)-(-2x-1/3(6-x)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3(6-x)!=0

x∈R



We add all the numbers together, and all the variables

2/3x-3(x+1)-(-2x-1/3(-1x+6)=0

We multiply parentheses

2/3x-3x-(-2x-1/3(-1x+6)-3=0

We calculate fractions


-3x+(6x(+3)/(9x^2(+3)+(-(-2x-1*3x)/(9x^2(+3)=0



We calculate terms in parentheses: +(6x(+3)/(9x^2(+3)+(-(-2x-1*3x)/(9x^2(+3), so:

6x(+3)/(9x^2(+3)+(-(-2x-1*3x)/(9x^2(+3

We can not solve this equation

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