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2/3x-17=2x-29x
We move all terms to the left:
2/3x-17-(2x-29x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2/3x-(-27x)-17=0
We get rid of parentheses
2/3x+27x-17=0
We multiply all the terms by the denominator
27x*3x-17*3x+2=0
Wy multiply elements
81x^2-51x+2=0
a = 81; b = -51; c = +2;
Δ = b2-4ac
Δ = -512-4·81·2
Δ = 1953
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1953}=\sqrt{9*217}=\sqrt{9}*\sqrt{217}=3\sqrt{217}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-3\sqrt{217}}{2*81}=\frac{51-3\sqrt{217}}{162} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+3\sqrt{217}}{2*81}=\frac{51+3\sqrt{217}}{162} $
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