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2/3x-14=x+13
We move all terms to the left:
2/3x-14-(x+13)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-x-13-14=0
We multiply all the terms by the denominator
-x*3x-13*3x-14*3x+2=0
Wy multiply elements
-3x^2-39x-42x+2=0
We add all the numbers together, and all the variables
-3x^2-81x+2=0
a = -3; b = -81; c = +2;
Δ = b2-4ac
Δ = -812-4·(-3)·2
Δ = 6585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-\sqrt{6585}}{2*-3}=\frac{81-\sqrt{6585}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+\sqrt{6585}}{2*-3}=\frac{81+\sqrt{6585}}{-6} $
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