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2/3x-1/6=3/4x-2
We move all terms to the left:
2/3x-1/6-(3/4x-2)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x-2)!=0We get rid of parentheses
x∈R
2/3x-3/4x+2-1/6=0
We calculate fractions
(-48x^2)/432x^2+288x/432x^2+(-324x)/432x^2+2=0
We multiply all the terms by the denominator
(-48x^2)+288x+(-324x)+2*432x^2=0
Wy multiply elements
(-48x^2)+864x^2+288x+(-324x)=0
We get rid of parentheses
-48x^2+864x^2+288x-324x=0
We add all the numbers together, and all the variables
816x^2-36x=0
a = 816; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·816·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*816}=\frac{0}{1632} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*816}=\frac{72}{1632} =3/68 $
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