2/3x-(2x+1)=-9

Solution for 2/3x-(2x+1)=-9 equation:

2/3x-(2x+1)=-9

We move all terms to the left:

2/3x-(2x+1)-(-9)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(2x+1)+9=0

We get rid of parentheses

2/3x-2x-1+9=0

We multiply all the terms by the denominator


-2x*3x-1*3x+9*3x+2=0

Wy multiply elements

-6x^2-3x+27x+2=0

We add all the numbers together, and all the variables

-6x^2+24x+2=0

a = -6; b = 24; c = +2;
Δ = b2-4ac
Δ = 242-4·(-6)·2
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{39}}{2*-6}=\frac{-24-4\sqrt{39}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{39}}{2*-6}=\frac{-24+4\sqrt{39}}{-12}
$