2/3x,+1/6=-3/4x+1

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Solution for 2/3x,+1/6=-3/4x+1 equation: 



2/3x.+1/6=-3/4x+1

We move all terms to the left:

2/3x.+1/6-(-3/4x+1)=0



Domain of the equation: 3x.!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4x+1)!=0

x∈R



We get rid of parentheses

2/3x.+3/4x-1+1/6=0

We calculate fractions


12x^2/(3x.*4x*6)+288x/(3x.*4x*6)+54x/(3x.*4x*6)-1=0

We add all the numbers together, and all the variables

12x^2/(+3x.*4x*6)+288x/(+3x.*4x*6)+54x/(+3x.*4x*6)-1=0

We multiply all the terms by the denominator


12x^2+288x+54x-1*(+3x.*4x*6)=0

We add all the numbers together, and all the variables

12x^2+342x-1*(+3x.*4x*6)=0

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