2/3x+9=(1/3x-2)

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Solution for 2/3x+9=(1/3x-2) equation: 



2/3x+9=(1/3x-2)

We move all terms to the left:

2/3x+9-((1/3x-2))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3x-2))!=0

x∈R



We calculate fractions


6x/9x^2+(-((1*3x)/9x^2+9=0

We add all the numbers together, and all the variables

6x/9x^2+(-((+1*3x)/9x^2+9=0

We calculate fractions

We do not support expression: x^4

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