2/3x+7/8=2/8x-3=

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Solution for 2/3x+7/8=2/8x-3= equation:



2/3x+7/8=2/8x-3=
We move all terms to the left:
2/3x+7/8-(2/8x-3)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 8x-3)!=0
x∈R
We get rid of parentheses
2/3x-2/8x+3+7/8=0
We calculate fractions
1024x/1536x^2+(-6x)/1536x^2+21x/1536x^2+3=0
We multiply all the terms by the denominator
1024x+(-6x)+21x+3*1536x^2=0
We add all the numbers together, and all the variables
1045x+(-6x)+3*1536x^2=0
Wy multiply elements
4608x^2+1045x+(-6x)=0
We get rid of parentheses
4608x^2+1045x-6x=0
We add all the numbers together, and all the variables
4608x^2+1039x=0
a = 4608; b = 1039; c = 0;
Δ = b2-4ac
Δ = 10392-4·4608·0
Δ = 1079521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1079521}=1039$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1039)-1039}{2*4608}=\frac{-2078}{9216} =-1039/4608 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1039)+1039}{2*4608}=\frac{0}{9216} =0 $

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