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2/3x+6/5x=15
We move all terms to the left:
2/3x+6/5x-(15)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
10x/15x^2+18x/15x^2-15=0
We multiply all the terms by the denominator
10x+18x-15*15x^2=0
We add all the numbers together, and all the variables
28x-15*15x^2=0
Wy multiply elements
-225x^2+28x=0
a = -225; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-225)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-225}=\frac{-56}{-450} =28/225 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-225}=\frac{0}{-450} =0 $
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