2/3x+5=99

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Solution for 2/3x+5=99 equation: 



2/3x+5=99

We move all terms to the left:

2/3x+5-(99)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

2/3x-94=0

We multiply all the terms by the denominator


-94*3x+2=0

Wy multiply elements

-282x+2=0

We move all terms containing x to the left, all other terms to the right

-282x=-2

x=-2/-282

x=1/141

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