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2/3x+5=5/2-x
We move all terms to the left:
2/3x+5-(5/2-x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x)!=-2
x!=-2/1
x!=-2
x∈R
2/3x-(-1x+5/2)+5=0
We get rid of parentheses
2/3x+1x+5-5/2=0
We calculate fractions
There is no solution for this equation
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